16x^2-20-63x=0

Solution for 16x^2-20-63x=0 equation:

16x^2-20-63x=0

a = 16; b = -63; c = -20;
Δ = b2-4ac
Δ = -632-4·16·(-20)
Δ = 5249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{5249}}{2*16}=\frac{63-\sqrt{5249}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{5249}}{2*16}=\frac{63+\sqrt{5249}}{32}
$